Determine the reaction coefficients for the conversion of methanol
into various hydrocarbons. The nonlinear model [12,17] that
describes the process is
Our formulation of the methanol-to-hydrocarbons problem as an
optimization problem follows [21,3]. We use a
-stage
collocation method, a uniform partition of the interval
with
intervals, and the standard [2, pages
247-249] basis representation,
| Variables |
|
| Constraints | |
| Bounds | 5 |
| Linear equality constraints | |
| Linear inequality constraints | 0 |
| Nonlinear equality constraints | |
| Nonlinear inequality constraints | 0 |
|
Nonzeros in
|
|
|
Nonzeros in |
|
We provide results for the AMPL formulation with
in Table
13.2. The initial values for
the
parameters are
.
The initial basis parameters are chosen so that
the collocation approximation is piecewise constant and
interpolates the data.
Data is generated by solving
numerically using
as given
in Maria [17] and applying a relative random perturbation of
size
. Figure 13.1 shows the solution and
the data.
| Solver | |
|
|
|
| LANCELOT | 196.62 s | 1792.75 s | |
|
|
|
9.02300e-03 | 9.00563e-03 | |
|
|
|
4.92130e-06 | 4.78630e-06 | |
|
| iterations | 251 | 622 | |
|
| LOQO | 2.13 s | 5.45 s | 18.78 s | 45.2 s |
|
|
9.02229e-03 | 9.02229e-03 | 9.02229e-03 | 9.02229e-03 |
|
|
3.5e-07 | 4.7e-08 | 1.7e-07 | 1.9e-08 |
| iterations | 19 | 21 | 30 | 26 |
| MINOS | 5.05 s | 13.49 s | 41.83 s | 263.67 s |
|
|
9.02228e-03 | 9.02229e-03 | 9.02228e-03 | 9.02228e-03 |
|
|
9.2e-13 | 9.8e-13 | 4.4e-12 | 3.5e-13 |
| iterations | 9 | 9 | 9 | 34 |
| SNOPT | 12.92 s | 32.38 s | 131.99 s | 512.16 s |
|
|
9.02228e-03 | 9.02229e-03 | 9.02228e-03 | 9.02228e-03 |
|
|
6.8e-09 | 9.8e-11 | 1.6e-09 | 1.3e-09 |
| iterations | 64 | 60 | 40 | 71 |
|
|
||||