Actual source code: baijsolvtran6.c

  1: #include <../src/mat/impls/baij/seq/baij.h>
  2: #include <petsc/private/kernels/blockinvert.h>

  4: PetscErrorCode MatSolveTranspose_SeqBAIJ_6_inplace(Mat A, Vec bb, Vec xx)
  5: {
  6:   Mat_SeqBAIJ       *a     = (Mat_SeqBAIJ *)A->data;
  7:   IS                 iscol = a->col, isrow = a->row;
  8:   const PetscInt    *r, *c, *rout, *cout;
  9:   const PetscInt    *diag = a->diag, n = a->mbs, *vi, *ai = a->i, *aj = a->j;
 10:   PetscInt           i, nz, idx, idt, ii, ic, ir, oidx;
 11:   const MatScalar   *aa = a->a, *v;
 12:   PetscScalar        s1, s2, s3, s4, s5, s6, x1, x2, x3, x4, x5, x6, *x, *t;
 13:   const PetscScalar *b;

 15:   PetscFunctionBegin;
 16:   PetscCall(VecGetArrayRead(bb, &b));
 17:   PetscCall(VecGetArray(xx, &x));
 18:   t = a->solve_work;

 20:   PetscCall(ISGetIndices(isrow, &rout));
 21:   r = rout;
 22:   PetscCall(ISGetIndices(iscol, &cout));
 23:   c = cout;

 25:   /* copy the b into temp work space according to permutation */
 26:   ii = 0;
 27:   for (i = 0; i < n; i++) {
 28:     ic        = 6 * c[i];
 29:     t[ii]     = b[ic];
 30:     t[ii + 1] = b[ic + 1];
 31:     t[ii + 2] = b[ic + 2];
 32:     t[ii + 3] = b[ic + 3];
 33:     t[ii + 4] = b[ic + 4];
 34:     t[ii + 5] = b[ic + 5];
 35:     ii += 6;
 36:   }

 38:   /* forward solve the U^T */
 39:   idx = 0;
 40:   for (i = 0; i < n; i++) {
 41:     v = aa + 36 * diag[i];
 42:     /* multiply by the inverse of the block diagonal */
 43:     x1 = t[idx];
 44:     x2 = t[1 + idx];
 45:     x3 = t[2 + idx];
 46:     x4 = t[3 + idx];
 47:     x5 = t[4 + idx];
 48:     x6 = t[5 + idx];
 49:     s1 = v[0] * x1 + v[1] * x2 + v[2] * x3 + v[3] * x4 + v[4] * x5 + v[5] * x6;
 50:     s2 = v[6] * x1 + v[7] * x2 + v[8] * x3 + v[9] * x4 + v[10] * x5 + v[11] * x6;
 51:     s3 = v[12] * x1 + v[13] * x2 + v[14] * x3 + v[15] * x4 + v[16] * x5 + v[17] * x6;
 52:     s4 = v[18] * x1 + v[19] * x2 + v[20] * x3 + v[21] * x4 + v[22] * x5 + v[23] * x6;
 53:     s5 = v[24] * x1 + v[25] * x2 + v[26] * x3 + v[27] * x4 + v[28] * x5 + v[29] * x6;
 54:     s6 = v[30] * x1 + v[31] * x2 + v[32] * x3 + v[33] * x4 + v[34] * x5 + v[35] * x6;
 55:     v += 36;

 57:     vi = aj + diag[i] + 1;
 58:     nz = ai[i + 1] - diag[i] - 1;
 59:     while (nz--) {
 60:       oidx = 6 * (*vi++);
 61:       t[oidx] -= v[0] * s1 + v[1] * s2 + v[2] * s3 + v[3] * s4 + v[4] * s5 + v[5] * s6;
 62:       t[oidx + 1] -= v[6] * s1 + v[7] * s2 + v[8] * s3 + v[9] * s4 + v[10] * s5 + v[11] * s6;
 63:       t[oidx + 2] -= v[12] * s1 + v[13] * s2 + v[14] * s3 + v[15] * s4 + v[16] * s5 + v[17] * s6;
 64:       t[oidx + 3] -= v[18] * s1 + v[19] * s2 + v[20] * s3 + v[21] * s4 + v[22] * s5 + v[23] * s6;
 65:       t[oidx + 4] -= v[24] * s1 + v[25] * s2 + v[26] * s3 + v[27] * s4 + v[28] * s5 + v[29] * s6;
 66:       t[oidx + 5] -= v[30] * s1 + v[31] * s2 + v[32] * s3 + v[33] * s4 + v[34] * s5 + v[35] * s6;
 67:       v += 36;
 68:     }
 69:     t[idx]     = s1;
 70:     t[1 + idx] = s2;
 71:     t[2 + idx] = s3;
 72:     t[3 + idx] = s4;
 73:     t[4 + idx] = s5;
 74:     t[5 + idx] = s6;
 75:     idx += 6;
 76:   }
 77:   /* backward solve the L^T */
 78:   for (i = n - 1; i >= 0; i--) {
 79:     v   = aa + 36 * diag[i] - 36;
 80:     vi  = aj + diag[i] - 1;
 81:     nz  = diag[i] - ai[i];
 82:     idt = 6 * i;
 83:     s1  = t[idt];
 84:     s2  = t[1 + idt];
 85:     s3  = t[2 + idt];
 86:     s4  = t[3 + idt];
 87:     s5  = t[4 + idt];
 88:     s6  = t[5 + idt];
 89:     while (nz--) {
 90:       idx = 6 * (*vi--);
 91:       t[idx] -= v[0] * s1 + v[1] * s2 + v[2] * s3 + v[3] * s4 + v[4] * s5 + v[5] * s6;
 92:       t[idx + 1] -= v[6] * s1 + v[7] * s2 + v[8] * s3 + v[9] * s4 + v[10] * s5 + v[11] * s6;
 93:       t[idx + 2] -= v[12] * s1 + v[13] * s2 + v[14] * s3 + v[15] * s4 + v[16] * s5 + v[17] * s6;
 94:       t[idx + 3] -= v[18] * s1 + v[19] * s2 + v[20] * s3 + v[21] * s4 + v[22] * s5 + v[23] * s6;
 95:       t[idx + 4] -= v[24] * s1 + v[25] * s2 + v[26] * s3 + v[27] * s4 + v[28] * s5 + v[29] * s6;
 96:       t[idx + 5] -= v[30] * s1 + v[31] * s2 + v[32] * s3 + v[33] * s4 + v[34] * s5 + v[35] * s6;
 97:       v -= 36;
 98:     }
 99:   }

101:   /* copy t into x according to permutation */
102:   ii = 0;
103:   for (i = 0; i < n; i++) {
104:     ir        = 6 * r[i];
105:     x[ir]     = t[ii];
106:     x[ir + 1] = t[ii + 1];
107:     x[ir + 2] = t[ii + 2];
108:     x[ir + 3] = t[ii + 3];
109:     x[ir + 4] = t[ii + 4];
110:     x[ir + 5] = t[ii + 5];
111:     ii += 6;
112:   }

114:   PetscCall(ISRestoreIndices(isrow, &rout));
115:   PetscCall(ISRestoreIndices(iscol, &cout));
116:   PetscCall(VecRestoreArrayRead(bb, &b));
117:   PetscCall(VecRestoreArray(xx, &x));
118:   PetscCall(PetscLogFlops(2.0 * 36 * (a->nz) - 6.0 * A->cmap->n));
119:   PetscFunctionReturn(PETSC_SUCCESS);
120: }

122: PetscErrorCode MatSolveTranspose_SeqBAIJ_6(Mat A, Vec bb, Vec xx)
123: {
124:   Mat_SeqBAIJ       *a     = (Mat_SeqBAIJ *)A->data;
125:   IS                 iscol = a->col, isrow = a->row;
126:   const PetscInt     n = a->mbs, *vi, *ai = a->i, *aj = a->j, *diag = a->diag;
127:   const PetscInt    *r, *c, *rout, *cout;
128:   PetscInt           nz, idx, idt, j, i, oidx, ii, ic, ir;
129:   const PetscInt     bs = A->rmap->bs, bs2 = a->bs2;
130:   const MatScalar   *aa = a->a, *v;
131:   PetscScalar        s1, s2, s3, s4, s5, s6, x1, x2, x3, x4, x5, x6, *x, *t;
132:   const PetscScalar *b;

134:   PetscFunctionBegin;
135:   PetscCall(VecGetArrayRead(bb, &b));
136:   PetscCall(VecGetArray(xx, &x));
137:   t = a->solve_work;

139:   PetscCall(ISGetIndices(isrow, &rout));
140:   r = rout;
141:   PetscCall(ISGetIndices(iscol, &cout));
142:   c = cout;

144:   /* copy b into temp work space according to permutation */
145:   for (i = 0; i < n; i++) {
146:     ii        = bs * i;
147:     ic        = bs * c[i];
148:     t[ii]     = b[ic];
149:     t[ii + 1] = b[ic + 1];
150:     t[ii + 2] = b[ic + 2];
151:     t[ii + 3] = b[ic + 3];
152:     t[ii + 4] = b[ic + 4];
153:     t[ii + 5] = b[ic + 5];
154:   }

156:   /* forward solve the U^T */
157:   idx = 0;
158:   for (i = 0; i < n; i++) {
159:     v = aa + bs2 * diag[i];
160:     /* multiply by the inverse of the block diagonal */
161:     x1 = t[idx];
162:     x2 = t[1 + idx];
163:     x3 = t[2 + idx];
164:     x4 = t[3 + idx];
165:     x5 = t[4 + idx];
166:     x6 = t[5 + idx];
167:     s1 = v[0] * x1 + v[1] * x2 + v[2] * x3 + v[3] * x4 + v[4] * x5 + v[5] * x6;
168:     s2 = v[6] * x1 + v[7] * x2 + v[8] * x3 + v[9] * x4 + v[10] * x5 + v[11] * x6;
169:     s3 = v[12] * x1 + v[13] * x2 + v[14] * x3 + v[15] * x4 + v[16] * x5 + v[17] * x6;
170:     s4 = v[18] * x1 + v[19] * x2 + v[20] * x3 + v[21] * x4 + v[22] * x5 + v[23] * x6;
171:     s5 = v[24] * x1 + v[25] * x2 + v[26] * x3 + v[27] * x4 + v[28] * x5 + v[29] * x6;
172:     s6 = v[30] * x1 + v[31] * x2 + v[32] * x3 + v[33] * x4 + v[34] * x5 + v[35] * x6;
173:     v -= bs2;

175:     vi = aj + diag[i] - 1;
176:     nz = diag[i] - diag[i + 1] - 1;
177:     for (j = 0; j > -nz; j--) {
178:       oidx = bs * vi[j];
179:       t[oidx] -= v[0] * s1 + v[1] * s2 + v[2] * s3 + v[3] * s4 + v[4] * s5 + v[5] * s6;
180:       t[oidx + 1] -= v[6] * s1 + v[7] * s2 + v[8] * s3 + v[9] * s4 + v[10] * s5 + v[11] * s6;
181:       t[oidx + 2] -= v[12] * s1 + v[13] * s2 + v[14] * s3 + v[15] * s4 + v[16] * s5 + v[17] * s6;
182:       t[oidx + 3] -= v[18] * s1 + v[19] * s2 + v[20] * s3 + v[21] * s4 + v[22] * s5 + v[23] * s6;
183:       t[oidx + 4] -= v[24] * s1 + v[25] * s2 + v[26] * s3 + v[27] * s4 + v[28] * s5 + v[29] * s6;
184:       t[oidx + 5] -= v[30] * s1 + v[31] * s2 + v[32] * s3 + v[33] * s4 + v[34] * s5 + v[35] * s6;
185:       v -= bs2;
186:     }
187:     t[idx]     = s1;
188:     t[1 + idx] = s2;
189:     t[2 + idx] = s3;
190:     t[3 + idx] = s4;
191:     t[4 + idx] = s5;
192:     t[5 + idx] = s6;
193:     idx += bs;
194:   }
195:   /* backward solve the L^T */
196:   for (i = n - 1; i >= 0; i--) {
197:     v   = aa + bs2 * ai[i];
198:     vi  = aj + ai[i];
199:     nz  = ai[i + 1] - ai[i];
200:     idt = bs * i;
201:     s1  = t[idt];
202:     s2  = t[1 + idt];
203:     s3  = t[2 + idt];
204:     s4  = t[3 + idt];
205:     s5  = t[4 + idt];
206:     s6  = t[5 + idt];
207:     for (j = 0; j < nz; j++) {
208:       idx = bs * vi[j];
209:       t[idx] -= v[0] * s1 + v[1] * s2 + v[2] * s3 + v[3] * s4 + v[4] * s5 + v[5] * s6;
210:       t[idx + 1] -= v[6] * s1 + v[7] * s2 + v[8] * s3 + v[9] * s4 + v[10] * s5 + v[11] * s6;
211:       t[idx + 2] -= v[12] * s1 + v[13] * s2 + v[14] * s3 + v[15] * s4 + v[16] * s5 + v[17] * s6;
212:       t[idx + 3] -= v[18] * s1 + v[19] * s2 + v[20] * s3 + v[21] * s4 + v[22] * s5 + v[23] * s6;
213:       t[idx + 4] -= v[24] * s1 + v[25] * s2 + v[26] * s3 + v[27] * s4 + v[28] * s5 + v[29] * s6;
214:       t[idx + 5] -= v[30] * s1 + v[31] * s2 + v[32] * s3 + v[33] * s4 + v[34] * s5 + v[35] * s6;
215:       v += bs2;
216:     }
217:   }

219:   /* copy t into x according to permutation */
220:   for (i = 0; i < n; i++) {
221:     ii        = bs * i;
222:     ir        = bs * r[i];
223:     x[ir]     = t[ii];
224:     x[ir + 1] = t[ii + 1];
225:     x[ir + 2] = t[ii + 2];
226:     x[ir + 3] = t[ii + 3];
227:     x[ir + 4] = t[ii + 4];
228:     x[ir + 5] = t[ii + 5];
229:   }

231:   PetscCall(ISRestoreIndices(isrow, &rout));
232:   PetscCall(ISRestoreIndices(iscol, &cout));
233:   PetscCall(VecRestoreArrayRead(bb, &b));
234:   PetscCall(VecRestoreArray(xx, &x));
235:   PetscCall(PetscLogFlops(2.0 * bs2 * (a->nz) - bs * A->cmap->n));
236:   PetscFunctionReturn(PETSC_SUCCESS);
237: }